Optimal. Leaf size=134 \[ \frac{(A (3-2 m)-B (2 m+5)) \cos (e+f x) (a \sin (e+f x)+a)^m \, _2F_1\left (2,m+\frac{1}{2};m+\frac{3}{2};\frac{1}{2} (\sin (e+f x)+1)\right )}{16 c^2 f (2 m+1) \sqrt{c-c \sin (e+f x)}}+\frac{(A+B) \cos (e+f x) (a \sin (e+f x)+a)^m}{4 f (c-c \sin (e+f x))^{5/2}} \]
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Rubi [A] time = 0.332324, antiderivative size = 134, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 38, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.105, Rules used = {2972, 2745, 2667, 68} \[ \frac{(A (3-2 m)-B (2 m+5)) \cos (e+f x) (a \sin (e+f x)+a)^m \, _2F_1\left (2,m+\frac{1}{2};m+\frac{3}{2};\frac{1}{2} (\sin (e+f x)+1)\right )}{16 c^2 f (2 m+1) \sqrt{c-c \sin (e+f x)}}+\frac{(A+B) \cos (e+f x) (a \sin (e+f x)+a)^m}{4 f (c-c \sin (e+f x))^{5/2}} \]
Antiderivative was successfully verified.
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Rule 2972
Rule 2745
Rule 2667
Rule 68
Rubi steps
\begin{align*} \int \frac{(a+a \sin (e+f x))^m (A+B \sin (e+f x))}{(c-c \sin (e+f x))^{5/2}} \, dx &=\frac{(A+B) \cos (e+f x) (a+a \sin (e+f x))^m}{4 f (c-c \sin (e+f x))^{5/2}}+\frac{\left (B c \left (-\frac{5}{2}-m\right )-A c \left (-\frac{3}{2}+m\right )\right ) \int \frac{(a+a \sin (e+f x))^m}{(c-c \sin (e+f x))^{3/2}} \, dx}{4 c^2}\\ &=\frac{(A+B) \cos (e+f x) (a+a \sin (e+f x))^m}{4 f (c-c \sin (e+f x))^{5/2}}+\frac{\left (\left (B c \left (-\frac{5}{2}-m\right )-A c \left (-\frac{3}{2}+m\right )\right ) \cos (e+f x)\right ) \int \sec ^3(e+f x) (a+a \sin (e+f x))^{\frac{3}{2}+m} \, dx}{4 a c^3 \sqrt{a+a \sin (e+f x)} \sqrt{c-c \sin (e+f x)}}\\ &=\frac{(A+B) \cos (e+f x) (a+a \sin (e+f x))^m}{4 f (c-c \sin (e+f x))^{5/2}}+\frac{\left (a^2 \left (B c \left (-\frac{5}{2}-m\right )-A c \left (-\frac{3}{2}+m\right )\right ) \cos (e+f x)\right ) \operatorname{Subst}\left (\int \frac{(a+x)^{-\frac{1}{2}+m}}{(a-x)^2} \, dx,x,a \sin (e+f x)\right )}{4 c^3 f \sqrt{a+a \sin (e+f x)} \sqrt{c-c \sin (e+f x)}}\\ &=\frac{(A+B) \cos (e+f x) (a+a \sin (e+f x))^m}{4 f (c-c \sin (e+f x))^{5/2}}+\frac{(A (3-2 m)-B (5+2 m)) \cos (e+f x) \, _2F_1\left (2,\frac{1}{2}+m;\frac{3}{2}+m;\frac{1}{2} (1+\sin (e+f x))\right ) (a+a \sin (e+f x))^m}{16 c^2 f (1+2 m) \sqrt{c-c \sin (e+f x)}}\\ \end{align*}
Mathematica [C] time = 23.8037, size = 5387, normalized size = 40.2 \[ \text{Result too large to show} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.293, size = 0, normalized size = 0. \begin{align*} \int{ \left ( a+a\sin \left ( fx+e \right ) \right ) ^{m} \left ( A+B\sin \left ( fx+e \right ) \right ) \left ( c-c\sin \left ( fx+e \right ) \right ) ^{-{\frac{5}{2}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B \sin \left (f x + e\right ) + A\right )}{\left (a \sin \left (f x + e\right ) + a\right )}^{m}}{{\left (-c \sin \left (f x + e\right ) + c\right )}^{\frac{5}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{{\left (B \sin \left (f x + e\right ) + A\right )} \sqrt{-c \sin \left (f x + e\right ) + c}{\left (a \sin \left (f x + e\right ) + a\right )}^{m}}{3 \, c^{3} \cos \left (f x + e\right )^{2} - 4 \, c^{3} -{\left (c^{3} \cos \left (f x + e\right )^{2} - 4 \, c^{3}\right )} \sin \left (f x + e\right )}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B \sin \left (f x + e\right ) + A\right )}{\left (a \sin \left (f x + e\right ) + a\right )}^{m}}{{\left (-c \sin \left (f x + e\right ) + c\right )}^{\frac{5}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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